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Comments
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Thanks!. just comment I can see both displacements, real and imaginary parts.?¿? I'm using v2.19.
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Hi DeAngelis, Thanks for comment. New subject so I appreciate it. you are plotting the imaginary values of the FRF Right. Just in some cases. The tool is not implemented yet and Mecway can't extract it properly yet. I had to choose the most no…
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Is frequency response.liml this? Yeessss. I need to incorporate this into Mecway's UI eventually I think it would be very appreciated. Meantime users can try with custom cards: Previous *STEP *FREQUENCY,STORAGE=YES is needed *STEP *STEAD…
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I have applied the procedure exposed above to the liml file DampedVibratingStrip.liml provided in the Examples of Mecway. I have first identified the dominant mode w1. (7.14 Rad/sec) As an example, I have determine the Damping coefficients for a des…
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No, I haven't try it. I will take a look. Thanks 3Rav.
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Thanks, JohnM and Sergio. Developers comment to me they are using the nonlinear Levenberg-Marquardt algorithm. Not much more information about it. -K. Levenberg, "A method for the solution of certain non-linear problems in least squares", Quart. Ap…
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Thank you, Sergio, I sent to you a private message. These two graphs compare how a well-known commercial software and the free curve Fit tool adjust a given set of experimental data. Not bad at all... In fact, it looks slightly better to me. The on…
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-¿Could this be one of those cases where the window goes out of screen or behind other unnoticed.?¿Could you try switching in between windows with the Alt TAB key combination to see if the second job monitor shows up.? -¿Are you running both files …
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If you are planning to reduce the time step, you could also reduce the number of elements. The brick is symmetric and BC also makes this a 2D problem.
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One could use this Nonlinear spring element to set up an only Compression or Only Tension Truss. Just provide the proper Reaction /Elongation Curve. NOTE: Do not confuse displacement with elongation. Not the same. It has puzzle me for a while. Mec…
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Thanks John, Not easy but it's worth the effort. It’s good to confirm the different tools work properly and understand their limitations. I have found that Contact can be slightly sticky so it’s not a good idea to abuse of the Stiffness parameter.…
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Block on top of a rigid surface with Friction coefficient of 0.4 . The block has start to slip at 21.789º. (Expected 21.801º)
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Ryzen 9 3.3 GHz 16GB 00:09:18 PardisoMKL OOC 00:05:16 Pastix
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Yep, I see the issue. Linear function like A=0.3*t is discretized with just two points. 0,0 1,0.0003 It makes the automatic time step to increase more and more as the convergence is going fine but it’s a false improvement for plasticity. That make…
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I think I found what is going on. Jakub Michalski on the ccx forum provided a good reference for the final PEEQ on this problem which help me to progress. For some reason that I still don’t fully understand, the automatic time increment setting , w…
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@Sebastianmaklary No. I wish it were that simple. Incremental plasticity and Hyperelastic models are Lagrangian, Deformation plasticity is Eulerian but will be updated to Logarithmic in next ccx version.
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This is not an easy subject I have recently understand. PEEQ seems right. Incremental plasticity provides the Lagrange Strain. To be able to compare with PEEQ you need to compute: Ln(sqrt(2*126+1))=2.77
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The frictionless supporting area is less stiff than the center nodes in the transverse direction. I think it's ok the necking initiates there and not in the center nodes which are attached from both sides.
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This is an example of what I’m referring. I have compute Prof M.Kraska example Tensile test on a wire. For the same BC/mesh/material/Time period and Time step configuration (Automatic) , Linear strain rate: Total CalculiX Time: 99.400074 Max P…
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I’m not suggesting there is a solver problem. I understand the linear model doesn’t initiate necking because it is just a matter of some insufficient mesh refinement, but there are still some differences in the final plastic strain depending on the …
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Thanks Sebastian, always interesting. My main concern now is that, if an analysis is timestep (or I would better said, time shape) dependent, I haven’t been paying enough attention to that point. I know some problems like thermal , are very sensiti…
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Oh!! . Thanks Sebastian, let's see the results when you get them.!!! Seems like for a uniformly stressed model, the plasticity may initiate anywhere. The first point to start will concentrate the plastic strains. Something like saying a tensile tes…
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I also like to ramp the load with a function in which the load is not always proportional to time. Sinus is a good option as it becomes gentler up to the end of the Time period when strains and stresses may become more extremes. It has the disadvant…
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I have found this very useful and I have use it for many years now. It is a free interpolation tool addon for Excel. Sometimes we get tabular results from an analisys that don't match with the desired time point or displacement increment. This tool …
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If I eliminate any one of the three options above, or reduce the speed for the centrifugal force, then it works. ¿Have you check there is no rigid body rotation?. ¿Are you able to load partial solution during the analysis? If yes, ¿How does the d…
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Thanks again harryvanlangen!! Yesterday I was thinking that this tool could be phenomenal to fillet corners . ¿Do you think that could be possible? I would say the final shape should be the cilinder after selecting a set of nodes in the corner. Prob…
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Congratulations Victor. Thermo-mechanical coupling will be very useful to me. Still need to do more tests but thermal effects combined with only compression and plasticity will be a powerful feature.
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SUUPER!!!. Great contribution. Thank you @harryvanlangen It sames to manage Shells and Solids too. !! It is like a super "project into surface". I can't wait to try on cicular platforms/handrails.
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To get the dynamic response just move the analysis type to dynamic and be sure to set up densities for all materials. (Mine has some damping)
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Hi, @AndreaC91 I have reformulated the Heavyside to see if it is clearer. Now the time (t) and the time offset (t0) are grouped so they both have the same time units and velocity is clearly identified. Amplitude*heaviside((v*(t-t0))-(x-width/2))*h…
