Yes, this is the only way I have found out. But in my specific case I have many nodes and it becomes coumbersome to deal with.
I hoped there would be another method.
I've sorted out. Results are equal now.
Can you please clarify the termis of the unittriangle() function?
unittriangle(0.5, (0.9*1.565)*t-40/(0.9*1.565)-x )
0.9*1.565 = velocity
40/(0.9*1.565) = it looks like space /velocity, but the unit of mea…
Provided that the function result unit is set correctly, the two functions should provide equal results.
[function in Pa]
-(180/4.3) * unittriangle(0.5, (0.9*1.565)*t-40/(0.9*1.565)-x )
[function in MPa]
-(180/4300/1000) * unittriangle(0.5, (0…
I'm not understanding the formula properly. The unit triangular function should have an unit area. Since I am simulating a 180 N travelling load, shouldn't I keep the same length (0.5 m) both in the unit triangular function and in its amplitude (500…
Thanks for your reply. I get better results now.
With the load formula you proposed, the traction is applied over a length of 1000 mm instead of 500 mm, isn't it?
Secondly, is it possibile to run a similar analysis on a beam model?
I also have a …