Andrea91

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Andrea91
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  • Yes, this is the only way I have found out. But in my specific case I have many nodes and it becomes coumbersome to deal with. I hoped there would be another method.
  • I've sorted out. Results are equal now. Can you please clarify the termis of the unittriangle() function? unittriangle(0.5, (0.9*1.565)*t-40/(0.9*1.565)-x ) 0.9*1.565 = velocity 40/(0.9*1.565) = it looks like space /velocity, but the unit of mea…
  • Provided that the function result unit is set correctly, the two functions should provide equal results. [function in Pa] -(180/4.3) * unittriangle(0.5, (0.9*1.565)*t-40/(0.9*1.565)-x ) [function in MPa] -(180/4300/1000) * unittriangle(0.5, (0…
  • I'm not understanding the formula properly. The unit triangular function should have an unit area. Since I am simulating a 180 N travelling load, shouldn't I keep the same length (0.5 m) both in the unit triangular function and in its amplitude (500…
  • Thanks for your reply. I get better results now. With the load formula you proposed, the traction is applied over a length of 1000 mm instead of 500 mm, isn't it? Secondly, is it possibile to run a similar analysis on a beam model? I also have a …
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