Looks like I missed one strut - 2 across and 2 up from the bottom left hand corner of the plan view.
Having thought about this question of buckling I have another few questions.
If the most critical member (chord or strut) failed the frame would …
@disla - I got so far following your suggested workflow. Unfortunately I was only able to get as far as isolating the compression members which I have included in a named group. Then I got lost due to lack of expertise
I have attached both my st…
@disla - “ They may work fine for static, but two nodes are insufficient to give good result in buckling analysis. See files.” The difference is quite startling! This answered my question.
Now that I understand this I will attempt to revise my mode…
Thank you for all very much for your replies. When I was in school - some 60 years ago I was told by my teacher that is good to ask questions . So please excuse me and let me, an amateur (non engineer) ask:-
@cwharpe -"This last result would hav…
Thank you very much Victor - I will look into this feature - it will save me a lot of time.
One more question if I may - is there also a similar feature to allocate component types between node arrays as in:-
1-2, 2-3, etc = component type 1, 3-4,4-…
@disla - thank you very much also for your response. The sections I have in mind are cold formed so therefore is the factor of safety 261/32 = >8. If so I suppose this appears very conservative but in the industry I used to work in, building and …
@cwharpe - thank you very very much for taking the time to provide me with such detailed answers to my questions. I have just read through them a couple of Tim’s over my morning coffee.
I have already learnt quite a lot from them, and I will examin…
Thanks Victor. My idea is for the skates to be set in channel tracks which in turn will be fixed to a concrete floor slab. Therefore the truss will only be able to travel backwards and forwards along the z axis.
Does this change the constraint arra…
Disla - thanks for getting back to me on this. Done it again - I suffer from zeros deficiency! Yes - 450 mpa steel is what I want in the model.
I also meant to say constraints as opposed to “restraints”.
@disla - "Be careful. There is a very common mistake. You have applied a TOTAL vertical force of -2.5KN to a “Set of 4 nodes”. That means each node gets -2.5Kn/4 = -0.625 kN."
I am very glad you pointed that out to me - a dangerous trap!
I think I …
@disla - "The L orientation doesn’t look fixed yet and some verticals are still trusses" . I think I have sorted this out now.
I came up with the same "mass" figure as you.
Also followed your instructions about reaction forces after adding a load o…
@Victor - thank you for answering my question about the reaction results.
I will explore and experiment with your suggestion about beam elements.
Regards
@ disla - I struggled with these rotations until I realised I had to be in the "select elements" view - classic newbie lack of understanding I suppose. I think I have it right now.
One thing that is puzzling me is that when I look at the results b…
Thank you very much for your response disla and for taking the trouble to look at my model.
First step - will change the rotation of the L members but I have another question. Should I set it to 0 or 90?
Second step - I will untick the truss feat…