I have to simulate contact between pin and tongs components.
Generally I study the components separately with forces obtained from hand calculation. Now I would have a comparison.
For first step is a good practice to set pressure overlosure E/t*10 considering the thickness equals to the pin diameter?
Pin diameter 60mm -> 210/0.06*10 = 35000 GPa*m
Thanks
Comments
The link and the pins have the same dimension of the studied model to have a first check on K value
Any rigid body degrees of freedom that are only constrained by contact, or in this case nothing at all, are at a high risk of flying away with very large displacements or failure to converge. They might not always do that if all forces happen to balance perfectly so it's possible that seemingly unrelated changes could trigger it.
Did you identify if it's rotating or expanding? I can't explain why it would expand without seeing the model, but rotating is what I expect it should do with only an axial constraint.
I think that some trouble are deriving from the solver. In fact for the simple test sometimes the solution is reached with a different numbers of iterations. This is not correct
On this new reference the pins on the axis of symmetry (both) will be free to go up and down but not laterally. This way you avoid more sofisticated BC’s out of plane.
Another aprox. would be to impose the lateral pins to move at a fixed distance from the central pin. (This option affects real tensile/compressive stress on the arms)
I have tested only in very basic models for small rotations and nonlinear, but it worked.
You can constrain initial radial distance to an arbitrary centre as (x-x0) and (y - y0) being x0 and y0 the coordinates of the arbitrary origin.